filename = "../../images/home-features/" . $imagename; $filename2 ... What does imagejpeg return? My guess would be that there are some permissions ...
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04 Variables en PHP
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Cap 04 del tutorial de *PHP* y MySQL por el Programador y Desarrollador de
Medios Interactivos Eduardo Suarez, CEO IT de falconproducciones.cl
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11 years ago
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